Rozwiąż równania:
a) 3 - ⅛x² = |x-3|
b) -x² +4x -1 = |2x-4|
Proszę o pomoc.
3 - ⅛x² = x -3 lub 3 - ⅛x² = 3 –x
3 - ⅛x² = x -3
3 - ⅛x – x + 3 = 0
- ⅛x – x + 6 = 0
Delta = 1 + 4 * ⅛ * 6 = 1 + 3 = 4
X1 =( 1 - 4) / 2* - ⅛ = -3/( -1/4) = 3 * 4 = 12
X2 = (1 + 4) / (-1/4) = 5 * (-4) = -20
3 - ⅛x² = 3 –x
3 - ⅛x² - 3 + x = 0
- ⅛x² + x = 0
X (- ⅛x + 1) = 0
X = 0 lub - ⅛x + 1= 0 to x = 8
-x² +4x -1 – 4 + 2x = 0
-x² + 6x - 5 = 0
Delta = 36 – 4 * (-1) * (-5) = 36 -20 = 16
Pirw z delty = 4
X1= -6 -4 / -2 = 5
X2= -6+4 / -2 = -2
-x² +4x -1 = 2x -4 lub -x² +4x -1= 4 – 2x
1. -x² +4x -1= 2x -4
- x² +4x -1- 2x +4=0
- x²+2x +3 = 0
Delta = 4 + 4* 3 = 4 + 12 = 16 pierwiastek z delty jest równy 4
X1 = -2 – 4 / 2 (-1) = -6 / -2 = 3
X2= -2 + 4 / -2 = -1
2. -x² +4x -1= 4 – 2x
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
a) 3 - ⅛x² = |x-3|
3 - ⅛x² = x -3 lub 3 - ⅛x² = 3 –x
3 - ⅛x² = x -3
3 - ⅛x – x + 3 = 0
- ⅛x – x + 6 = 0
Delta = 1 + 4 * ⅛ * 6 = 1 + 3 = 4
X1 =( 1 - 4) / 2* - ⅛ = -3/( -1/4) = 3 * 4 = 12
X2 = (1 + 4) / (-1/4) = 5 * (-4) = -20
3 - ⅛x² = 3 –x
3 - ⅛x² - 3 + x = 0
- ⅛x² + x = 0
X (- ⅛x + 1) = 0
X = 0 lub - ⅛x + 1= 0 to x = 8
-x² +4x -1= 4 – 2x-x² +4x -1 – 4 + 2x = 0
-x² + 6x - 5 = 0
Delta = 36 – 4 * (-1) * (-5) = 36 -20 = 16
Pirw z delty = 4
X1= -6 -4 / -2 = 5
X2= -6+4 / -2 = -2
b) -x² +4x -1 = |2x-4|
-x² +4x -1 = 2x -4 lub -x² +4x -1= 4 – 2x
1. -x² +4x -1= 2x -4
- x² +4x -1- 2x +4=0
- x²+2x +3 = 0
Delta = 4 + 4* 3 = 4 + 12 = 16 pierwiastek z delty jest równy 4
X1 = -2 – 4 / 2 (-1) = -6 / -2 = 3
X2= -2 + 4 / -2 = -1
2. -x² +4x -1= 4 – 2x
-x² +4x -1 – 4 + 2x = 0
-x² + 6x - 5 = 0
Delta = 36 – 4 * (-1) * (-5) = 36 -20 = 16
Pirw z delty = 4
X1= -6 -4 / -2 = 5
X2= -6+4 / -2 = -2