Question

Rozwiąż równania

5ptk za każdy punkt;]

Dam naj;]

Answer 1

a]

(3-x)²-(x+⅓)²=²/₉

9-6x+x²-x²-⅔x-¹/₉=²/₉

-6⅔x=²/₉-8²/₉

-²⁰/₃x=²/₉-⁷⁴/₉

x=-8:-²⁰/₃

x=²⁴/₂₀

x=1⅕

b]

4(½x-3]²-(2-x)²=0

4[¼x²-3x+9)-4+4x-x²=0

x²-12x+36-4+4x-x²=0

-8x=-32

x=-32;-8

x=4

c]

(6+⅓x)(-⅓x+6)+(⅓x-4)²=4

36-¹/₉x²+¹/₉x²-⁸/₃x+16=4

-⁸/₃x=4-52

x=-48;-⁸/₃

x=18

d]

(-4x-3)(4x-3)+8(1-√2x)²=1

-16x²+9+8[1-2√2x+2x²)=1

-16x²+9+8-16√2x+16x²=1

-16√2x=1-17

-16√2x=-16/:-16

√2x=1

x=1/√2

x=√2/2