Rozwiąż równania kwadratowe : 2x (kwadrat) - 4 = (x+1)(x+2)
(2x+1)² - 4x -1 = (x+1)(x+2)
4x² + 4x + 1 -4x + 1 =x²+2x+x+2
3x²-2x-2=0
Δ = b² - 4ac
Δ = 4+32=36
ѴΔ = Ѵ169 = 6
x₁ =(-b-ѴΔ)/2a = 2-6/6=-1/3
x₂ =(-b+ѴΔ)/2a = 8/6= 1 i 1/3
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(2x+1)² - 4x -1 = (x+1)(x+2)
4x² + 4x + 1 -4x + 1 =x²+2x+x+2
3x²-2x-2=0
Δ = b² - 4ac
Δ = 4+32=36
ѴΔ = Ѵ169 = 6
x₁ =(-b-ѴΔ)/2a = 2-6/6=-1/3
x₂ =(-b+ѴΔ)/2a = 8/6= 1 i 1/3