December 2018 1 47 Report
Rozwiąż równania:
a)  (2-3x)^{2} - (1+2x)^{2} - 3x^{2} = 2 x^{2}
b)  (\sqrt{3y} +2) ^{2} - ( \sqrt{3y} +2) ( \sqrt{3y} -2) = 0
c)  \frac{(2x- \sqrt{2)} (2x+ \sqrt{2)} }{2} - \frac{6(x-1) ^{2} }{3} =3

Daję NAJ :)
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