Question

Rozwiąż równania:
a) 2(5a-3) -a-4(3a-2)=0
b)⅖(x -2)=x+4
c)3y-2(y-1)= -6
d)¼z+(z-6)=⅔(z-2)

Answer 1

A)
2(5a-3)-a-4(3a-2)=0
10a - 6 - a -12a +8 = 0
-3a +2 = 0
-3a = -2

Answer 2

A) 2(5a-3) -a-4(3a-2)=0

10a - 3 - a - 10a + 8 = 0

10a - a - 10a = 0 +3 - 8

-a = -5 / : (-1)
a = 5

b)⅖(x -2)=x+4

⅖ x - 4/5 = x + 4 /* 5
2x - 4 = 5x + 20
2x - 5x = 20 + 4
-3x = 24 / : (-3)
x = -8

c)3y-2(y-1)= -6

3y - 2y + 2 = -6
y = -6 -2
y= -8

d)¼z+(z-6)=⅔(z-2)

¼z² - 1 ½ z = ⅔z - 1 1/3 / : z

¼z - 1 ½ = ⅔ - 1 1/3 / *12

3z - 18 = 8 - 16
3z = 8 - 16 + 18

3z = 10 / : 3

z = 3 1/3


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