rozwiąż rówania wielomianoe:
2x²+8x²+3x+12=0
x³-2x²-4x+8=0
x³+3x²-x-3=0
-x³+5x²-x+5=0
2x³+8x²+3x+12 = 0
2x²(x+4)+3(x+4) = 0
(2x²+3)(x+4) = 0
2x²+3 > 0
x+4 = 0
x = -4
====
x³-2x²-4x+8 = 0
x²(x-2)-4(x-2) = 0
(x²-4)(x-2) = 0
(x+2)(x-2)(x-2) = 0
x+2 = 0 => x = -2
lub
x-2 = 0 => x = 2
Odp. x = -2 v x = 2
x³+3x²-x-3 = 0
x²(x+3)-(x+3) = 0
(x+3)(x²-1) = 0
(x+3)(x+1)(x-1) = 0
x+3 = 0 => x = -3
x+1 = 0 => x = -1
x-1 = 0 = x = 1
Odp. x = -3 v x = -1 v x = 1
-x³+5x²-x+5 = 0
x²(-x+5)+(-x+5) = 0
(x²+1)(-x+5) = 0
x²+1 > 0
-x+5 = 0
-x = -5
x = 5
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2x³+8x²+3x+12 = 0
2x²(x+4)+3(x+4) = 0
(2x²+3)(x+4) = 0
2x²+3 > 0
x+4 = 0
x = -4
====
x³-2x²-4x+8 = 0
x²(x-2)-4(x-2) = 0
(x²-4)(x-2) = 0
(x+2)(x-2)(x-2) = 0
x+2 = 0 => x = -2
lub
x-2 = 0 => x = 2
Odp. x = -2 v x = 2
x³+3x²-x-3 = 0
x²(x+3)-(x+3) = 0
(x+3)(x²-1) = 0
(x+3)(x+1)(x-1) = 0
x+3 = 0 => x = -3
lub
x+1 = 0 => x = -1
lub
x-1 = 0 = x = 1
Odp. x = -3 v x = -1 v x = 1
-x³+5x²-x+5 = 0
x²(-x+5)+(-x+5) = 0
(x²+1)(-x+5) = 0
x²+1 > 0
-x+5 = 0
-x = -5
x = 5
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