Rozwiąż nierówność:
zalozenie
x² -3x+2≠0
Δ=9-8=1
x₁=(3-1)/2=2/2=1
x₂=(3+1)/2=4/2=2
D=R\{1,2}
3x+1 <0 /(x²-3x+2 )²
x²-3x+2
(3x+1)(x²-3x+2 )<0
(3x+1)(x-1)(x-2)<0
3x+1=0
3x= -1
x= -⅓
-⅓ ++++++++ 1 2 ++++++ >x
- - -- - -- - - -- - - - - -- - --
x∈(-∞,-⅓)u(1,2)
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zalozenie
x² -3x+2≠0
Δ=9-8=1
x₁=(3-1)/2=2/2=1
x₂=(3+1)/2=4/2=2
D=R\{1,2}
3x+1 <0 /(x²-3x+2 )²
x²-3x+2
(3x+1)(x²-3x+2 )<0
(3x+1)(x-1)(x-2)<0
3x+1=0
3x= -1
x= -⅓
-⅓ ++++++++ 1 2 ++++++ >x
- - -- - -- - - -- - - - - -- - --
x∈(-∞,-⅓)u(1,2)