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Δ=1+8=9 √Δ=3
x1=(-1-3)/4=-1 x2=2/4=1/2
D: x∈(-∞,-1)∨(1/2,+∞)
1°: x∈(-∞,-1>∨<1/2,+∞)∧2x-1<0→x∈(-∞,-1>
2° 2x+1≥0→x≥1/2 podnosze strony do kwadratu
2x²+x-1>4x²-4x+1
2x²-5x+2<0
Δ=25-16=9
x1=(5-3)/4=1/2,15 x2=(5+3)/4=2
ODP x∈(-∞,-1>∨(1/2 , 2)