September 2018 1 79 Report

Rozwiąż nierówność:

1) (n po 2)\leq4, gdy n należy do N i n≥2

2) n^{2}+1<(n+2 po 2), gdy n należy do N

3) x\sqrt{x^2}}-6x+7\geq0

4) x^{4}-7x^{2}+12\geq0

Odp:

1) {2,3}

2) {1,2}

3) <-7;3-√2)u<3+√2;+∞)

4) <-∞;-2>u<-√3;√3>u<2;+∞)


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