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x²(2x - 3) - 16(2x - 3) = 0
(x² - 16) (2x - 3) = 0
x²(2x-3)-16(2x-3)≤0
(x²-16)(2x-3)≤0
(x²-16) ---> (x-4)(x+4)
(2x-3) ---> 2x=3 /:2 x= 1 1/2
zatem rozwiazaniem sa -4, 4 oraz 1 1/2