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2x²-x=0 ∨ 2x²+11x-6=0
x=0 ∨ x=¹/₂ ∨ Δ=121+48=169 √Δ=13
x₁=-6 ∨ x₂=¹/₂
x ∈ <0,6>
b)
x²(4x+3)-2(4x+3)>0
(x²-2)(4x+3)>0
x²-2=0 ∨ 4x+3=0
x=√2 ∨ x=-√2 ∨ x=-³/₄
x ∈ (-√2;-³/₄) ∧ (√2;+∞)
c)
x²(-3x²+10x+25)<0
x=0 ∨ -3x²+10x+25=0
Δ=100+300=400 √Δ=20
x₁=5 ∨ x₂=-⁵/₂
x ∈ (-⁵/₂;0) ∧ (6;+∞)