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możemy obliczyć to z delty więc
Δ = 100 - 4 * (-5) * 0 = 100
√100 = 10
x1 = (-10 - 10 ) / -10 = 2
x2 = (-10 +10) / -10 = 0
--|-----------------|----------------->
0 2
W obydwu miejscach kółeczko otwarte, ramiona paraboli do dołu x∈(0,2)