Rozwiąż nierówność: √2X+4<√8x-8
√2x+4 < √8x-8
√2x-√8x < -8-4
√2x-√(4·2)x < -12
√2x-√4·√2x < -12
√2x-2√2x < -12
(√2-2√2)x < -12
-√2x < -12
√2x > 12 /:√2
x > 12/√2 · √2/√2
x > 12√2/2
x > 6√2
x ∈ (6√2; +∞)
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√2x+4 < √8x-8
√2x-√8x < -8-4
√2x-√(4·2)x < -12
√2x-√4·√2x < -12
√2x-2√2x < -12
(√2-2√2)x < -12
-√2x < -12
√2x > 12 /:√2
x > 12/√2 · √2/√2
x > 12√2/2
x > 6√2
x ∈ (6√2; +∞)