Rozwiąż nierówność: √2X+4<2√2x-8
√2x+4 < 2√2x-8
√2x-2√2x < -8-4
-√2x < -12
√2x > 12 /:√2
x > 12/√2 · √2/√2
x > 12√2/2
x > 6√2
x ∈ (6√2; +∞)
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√2x+4 < 2√2x-8
√2x-2√2x < -8-4
-√2x < -12
√2x > 12 /:√2
x > 12/√2 · √2/√2
x > 12√2/2
x > 6√2
x ∈ (6√2; +∞)