" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
|1-x|+|3-x|>4 ∧x∈(-∞,1>
1-x+3-x>4
-2x>0
x<0
x∈(-∞,1>∧x<0→x∈(-∞,0)
|1-x|+|3-x|>4 ∧ x∈(1,3>
-1+x+3-x>4
2>4
x∈pustego
x∈(1,3>∧x∈pustego →x∈zbior pusty
|1-x|+|3-x|>4 ∧ x∈(3,∞)
-1+x-3+x>4
2x>8
x>4
x∈(3,∞) ∧ x>4→(4,∞)
zatem rozw jest
x∈(-∞,0)u(4,∞)