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x²-4x+4≥0
(x-2)² ≥ 0 tozsamosc
x∈ R
2)
-5 ≥ (x-2)²
nierownosc sprzeczna
3)
(4-x)(x-5) >0
m.z. x=4 v x=5
____4____5____>0
_ _ 0 + + 0 _ +
Odp. x∈(4, 5)