Question

Rozwiąż mi proszę takie równanie :) :

x3+4x2-2x-8=0

Answer 1

x³ + 4x² - 2x - 8 = 0

x²·(x + 4) - 2·(x + 4) = 0

(x + 4)(x² - 2) = 0

(x + 4)(x - √2)(x + √2) = 0

x + 4 = 0 lub x - √2 lub x + √2 = 0

 

x + 4 = 0

x = - 4

 

x - √2 = 0

x = √2

 

x + √2 = 0

x = - √2

 

Odp. x = - 4 lub x = - √2 lub x = √2