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x²+(y+1)²=3
-x²+y+4=0
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x²=y+4
y+4+y²+2y+1=3
y²+3y+2=0
Δ=9-8=1 √Δ=1
y1=(-3-1)/2=-2
y2=(-3+1)/2=-1
x²=2 ∨ x²=3
x11=√2 x12=-√2
A1(-1,-√2) A2(-1,√2)
x²=3
x21=-√3 x22=√3
B1(-2,-√3) A2(-2,√3)
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