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-x²+ y + 4 = 0→y=x²-4
Przyjme nowa niewiadoma:
u=x²
u+(u-3)²=3
u²-5u+6=0
Δ=25-24=1 √Δ=1
u1=(5-1)/2=2
u2=(5+1)/2=3
x²=2→
x11=-√2 y11=-2 A11(-√2,-2)
x12=+√2 y12=-2 A11(√2,-2)
x²=3→
x11=-√3 y11=-1 B11(-√3,-1)
x12=+√3 y12=-1 B11(√3,-1)
Jakis problem z zalacznikiem