a)
x² - 5x + 4 > 0
Δ = b² - 4ac = (-5)² -4 * 1 * 4 = 25 - 16 = 9
√Δ = √9 = 3
a > 0
x ∈ (-∞ , 1) u (4, +∞)
b)
-x(x+6)<9
-x² - 6x - 9 < 0
Δ = b² - 4ac = (-6)² - 4 * (-1) * (-9) = 36 -36 = 0
√Δ = √0 = 0
a < 0
x ∈ (-∞ , -3) u (-3, +∞)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
a)
x² - 5x + 4 > 0
Δ = b² - 4ac = (-5)² -4 * 1 * 4 = 25 - 16 = 9
√Δ = √9 = 3
a > 0
x ∈ (-∞ , 1) u (4, +∞)
b)
-x(x+6)<9
-x² - 6x - 9 < 0
Δ = b² - 4ac = (-6)² - 4 * (-1) * (-9) = 36 -36 = 0
√Δ = √0 = 0
a < 0
x ∈ (-∞ , -3) u (-3, +∞)