Rozwiąż :
10(y+2)+x-5=x-5
25(y+2)+3(x-5)=(-10)
To jest układ równań :> Z góry dziękuje :D
10y +20 +x -x =-5 +5
25y +50 +3x -15 =-10
10y = -20 /:10
25y +3x = -45
y=-2
-50+3x =-45
3x = 5 /:3
x=1 2/3
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10y +20 +x -x =-5 +5
25y +50 +3x -15 =-10
10y = -20 /:10
25y +3x = -45
y=-2
-50+3x =-45
3x = 5 /:3
x=1 2/3
x=1 2/3
y=-2