Rozłóż wielomian W(x)=3x³-2x²-9x+6 na czynniki
Rozwiaż równanie 2x³-3x²+x=0
Rozwiaż nierówność 2x²-3x-2≤0
1) W(x)= 3x³-2x²-9x+6 = x²(3x-2)-3(3x-2)= (x²-3)(3x-2)= (x- √ 9)(x+ √ 9)(3x-2)
2) 2x³-3x²+x=0
x(2x²-3x+1)=0
x=0 2x²-3x+1=0
Δ =b^2 -4ac
Δ= (-3)^2-4 *2*1=1
√Δ=1
x1=-b- √Δ /2a
x1= 3-1/2*2=2/4=1/2
x2= -b+ √Δ /2a
x2= 3+1/2*2=4/4=1
3) 2x²-3x-2≤0
Δ =(-3)^2-4*2*(-2)=25
√Δ =5
x1= -b- √Δ /2a
x1= 3-5/2*2= -2/4= -1/2
x2= 3+5/2*2= 8/4= 2
W(x)=3x³-2x²-9x+6=
=x²(3x-2)-3(3x-2)=
=(3x-2)(x²-3)=
=(3x-2)(x-√3)(x+√3)
2x³-3x²+x=0
x=0
2x²-3x+1=0
Δ=(-3)²-4*1*1=9-8=1
x₁=(3+1)/4=4/4=1
x₂=(3-1)/4=2/4=½
x=0 ∨ x=1 ∨ x=½
2x²-3x-2≤0
Δ=(-3)²-4*2*(-2)=9+16=25
√Δ=5
x₁=(3+5)/4=8/4=2
x₂=(3-5)/4=-2/4=-½
x∈<-½;2>
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1) W(x)= 3x³-2x²-9x+6 = x²(3x-2)-3(3x-2)= (x²-3)(3x-2)= (x- √ 9)(x+ √ 9)(3x-2)
2) 2x³-3x²+x=0
x(2x²-3x+1)=0
x=0 2x²-3x+1=0
Δ =b^2 -4ac
Δ= (-3)^2-4 *2*1=1
√Δ=1
x1=-b- √Δ /2a
x1= 3-1/2*2=2/4=1/2
x2= -b+ √Δ /2a
x2= 3+1/2*2=4/4=1
3) 2x²-3x-2≤0
Δ =b^2 -4ac
Δ =(-3)^2-4*2*(-2)=25
√Δ =5
x1= -b- √Δ /2a
x1= 3-5/2*2= -2/4= -1/2
x2= -b+ √Δ /2a
x2= 3+5/2*2= 8/4= 2
W(x)=3x³-2x²-9x+6=
=x²(3x-2)-3(3x-2)=
=(3x-2)(x²-3)=
=(3x-2)(x-√3)(x+√3)
2x³-3x²+x=0
x(2x²-3x+1)=0
x=0
2x²-3x+1=0
Δ=(-3)²-4*1*1=9-8=1
√Δ=1
x₁=(3+1)/4=4/4=1
x₂=(3-1)/4=2/4=½
x=0 ∨ x=1 ∨ x=½
2x²-3x-2≤0
Δ=(-3)²-4*2*(-2)=9+16=25
√Δ=5
x₁=(3+5)/4=8/4=2
x₂=(3-5)/4=-2/4=-½
x∈<-½;2>