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[x³+3x²+3x+1]:[x+1]=x²+2x+1
-x³-x²
...........
== 2x²+3x+1
-2x²-2x
......................
==== x+1
-x-1
....................
====
x³+3x²+3x+1=[x+1][x²+2x+1]=(x+1)[x+1)²=(x+1)(x+1)(x+1)
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[x³+3x²+3x+1]:[x+1]=x²+2x+1
-x³-x²
...........
== 2x²+3x+1
-2x²-2x
......................
==== x+1
-x-1
....................
====
x³+3x²+3x+1=[x+1][x²+2x+1]=(x+1)[x+1)²=(x+1)(x+1)(x+1)