Równanie z niewiadomą 't'.
s=60
u=2
a=9.8
t=?
Z gory dziekuje za pomoc!
-0,5*9,8t² - 2t + 60 = 0
-4,9t²-2t+60=0
Δ=b²-4ac = 4 + 1176 = 1180
√Δ=√1180=2√295
t1=(-b-√Δ)/2a = (2-2√295)/-9,8 = 2(1-√295)/-9,8 = -(1-√295)/4,9
t2 = (-b+√Δ)/2a = -(1+√295)/4,9
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-0,5*9,8t² - 2t + 60 = 0
-4,9t²-2t+60=0
Δ=b²-4ac = 4 + 1176 = 1180
√Δ=√1180=2√295
t1=(-b-√Δ)/2a = (2-2√295)/-9,8 = 2(1-√295)/-9,8 = -(1-√295)/4,9
t2 = (-b+√Δ)/2a = -(1+√295)/4,9