równanie równanie:
x(2x+3)-(x+1)(x-1)=(x+3)2
z góry dzięki za odp. ;)
x(2x+3)-(x+1)(x-1)=(x+3)^2
2x^2+3x-x^2+x-x+1=x^2+2*x*3+9
2x^2-x^2+3x+1=x^2+6x+9=0
2x^2-x^2-x^2+3x-6x+1-9=0
-3x-8=0
a=0 b= -3 c= -8
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x(2x+3)-(x+1)(x-1)=(x+3)^2
2x^2+3x-x^2+x-x+1=x^2+2*x*3+9
2x^2-x^2+3x+1=x^2+6x+9=0
2x^2-x^2-x^2+3x-6x+1-9=0
-3x-8=0
a=0 b= -3 c= -8