January 2019 1 40 Report
Równanie - x^{2} + ax + b=0 ma dwa niezerowe pierwiastki  x_{1} i x_{2} takie, że  \frac{1}{ x_{1} } + \frac{1}{ x_{2} } \ \textgreater \ 0.Współczynniki a i b spełniają warunek:
a. a>0 i b>0
b. a<0 i b<0
c. ab>0
d. ab<0

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