robotnik o masie 65kg niesie worek o masie 25 kg jaka siła naciska na ziemię ??
F=m*g
m=65+25=90 kg
g=9,8 m/s²
F=9,8*90
F=882 N
dane;
m = (65+25)kg = 90 kg
g = 10 m/s2 = 10 N/kg
szukane:
F = ?
F = m *g
F = 90kg *10N/kg
F = 900 N = 0,9 kN
=================
Odp.Szukana siła nacisku wynosi 900 N (0,9 kN).
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F=m*g
m=65+25=90 kg
g=9,8 m/s²
F=9,8*90
F=882 N
dane;
m = (65+25)kg = 90 kg
g = 10 m/s2 = 10 N/kg
szukane:
F = ?
F = m *g
F = 90kg *10N/kg
F = 900 N = 0,9 kN
=================
Odp.Szukana siła nacisku wynosi 900 N (0,9 kN).