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(5y+1)(4y-1)
4 y + 1
(X)
5 y - 1
(4 y) (5 y) = 20 y²
5y (+1) + 4y (-1) = + 5y - 4y = + y
(+1) (-1) = -1
Finalmente:
20 y² + y - 1 = (4y + 1) ( 5y - 1)