Resuelve los siguientes sistemas de 3×3 con el método de determinantes.
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1-) x/3 + y = 2z + 3
x - y = 1
x + z = y/4 + 11
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x + 3y - 6z = 9
x - y = 1
4x - y + 4z = 44
D₁=![\left[\begin{array}{ccc}9&3&-6\\1&-1&0\\44&-1&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%263%26-6%5C%5C1%26-1%260%5C%5C44%26-1%264%5Cend%7Barray%7D%5Cright%5D "\left[\begin{array}{ccc}9&3&-6\\1&-1&0\\44&-1&4\end{array}\right]")
D₂=![\left[\begin{array}{ccc}1&9&-6\\1&1&0\\4&44&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%269%26-6%5C%5C1%261%260%5C%5C4%2644%264%5Cend%7Barray%7D%5Cright%5D "\left[\begin{array}{ccc}1&9&-6\\1&1&0\\4&44&4\end{array}\right]")
D₃=![\left[\begin{array}{ccc}1&3&9\\1&-1&1\\4&-1&44\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%269%5C%5C1%26-1%261%5C%5C4%26-1%2644%5Cend%7Barray%7D%5Cright%5D "\left[\begin{array}{ccc}1&3&9\\1&-1&1\\4&-1&44\end{array}\right]")
D = -34
D₁ = -306 /34
D₂ = -272 /34
D₃ = -136 /34
x = 9
y = 8
z = 4
2-) 6x/5 + y + z - 4= 19/5
z - 4 + 6x - 19/5 = -y
4z + 3y = 3x - y
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6x + 5y + 5z = 39
6x + 5y + 5z = 39
-3x + 4y + 4z = 0
---------------------------
x = 4
x = 3-z
z= z
z ∈ R
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