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SOLUCION:
______________
-(2) ± √ (2)² - 4(1)(2)
x = -----------------------------------------
2(1)
_________
- 2 ± √ 4 - 8
x = --------------------------------
2
______
-2 ± √ - 4
x = -------------------------
2
________
-2 ± √ 4 × - 1
x = --------------------------
2
___
- 2 ± 2 √-1
x = --------------------------
2
- 2 ± 2 i
x = ---------------------
2
x = - 1 ± 1 i
ENTONCES:
x₁ = - 1 + 1 i
x₂ = - 1 - 1 i
RTA:
⇒ x = { (- 1 + 1 i) , (- 1 - 1 i) }