" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
3y-4z=25 reemplazo y 3(3x/2)-4z=25
9x/2-4z =25 despejo x aqui
9x/2=25+4z
9x=2(25+4z)
x=50+8z
-5x+z=-14 reemplazo x -5(50+8z)+z=-14
-250-40z+z=-14
-250+14= 40z-z
-236=39z
z= -236/39
-5x+z=-14
-5x-236/39=-14
-236/39+14=5x
(-236+14(39))/39=5x
310/(39)(5) =x
62/39=x
como y=3x/2 entonces y=3(62/39)/2
y=186/78
y=93/39