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2 ⇒1/2x12⇒6
3 ⇒1/3x12⇒4
6⇒1/6x12⇒2
∴4k+2k+6k=600
12k=600
k=50
Dar la parte intermedia osea 4k
4k⇒4(50)⇒200
Rpta: 200