średnicą koła wielkiego kuli jest równa 12cm ile wynosi objetosc tej kuli ??
d = 2 r = 12 cm
zatem r = 6 cm
oraz objętość kuli
V = (4/3) pi *r^3
V = (4/3) pi *( 6 cm)^3 = (4/3)* pi *216 cm^3 = 288 pi cm^3
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kolo wielkie kuli ma srednice rowna 2r=12cm
to r=12/2=6cm
objetosc kuli:
V=4/3 π·r³
V=4/3 π ·6³=4/3 π ·216 =864π/3 =288π cm³
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d = 2 r = 12 cm
zatem r = 6 cm
oraz objętość kuli
V = (4/3) pi *r^3
V = (4/3) pi *( 6 cm)^3 = (4/3)* pi *216 cm^3 = 288 pi cm^3
=========================================================
kolo wielkie kuli ma srednice rowna 2r=12cm
to r=12/2=6cm
objetosc kuli:
V=4/3 π·r³
V=4/3 π ·6³=4/3 π ·216 =864π/3 =288π cm³