Średnia moc silnika samochodu poruszającego się z prędkością 72 [km\h] wynosi 40 kW. Ile wynosi siła ciągu tego samochodu?
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V = 72 km/h = 72 * 1000 m/3600 s = 20 m/s
P = 40 kW = 40000 W = 40000 J/s
F = ?
P = W /t ale W = F * s
P = F * s /t ale s/t = V
P = F * V
F = P / V
F = 40000 J/s /20 ms
F = 2000 N = 2 kN
[ J/s /m/s ] = [ J/s * s/m] = [J/m ] = [ N * m /m] = [ N]
dane:
v = 72 km/h = 72 *1000m/3600s = 20 m/s
P = 40 kW = 40 000 W = 40 000 J/s = 40 000 N*m/s
szukane:
F = ?
P = W/t = F*s/t
ale: s/t = v, zatem:
P = F * v /:v
F = P/v = 40000N*m/s :20m/s = 2 000 N
1 kN = 1000 N
F = 2 kN
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Odp.Siła ciągu tego samochodu wynosi 2 kN (kiloniutony)