Rahayu mendekatkan wajahnya sampai 15 cm di depan sebuah cermin . Ia melihat bintik-bintik jerawatnya menjadi 2 kali lebih besar . Berapakah jari-jari kelengkungan cermin yang digunakan Rahayu?
shashadini
Misal : jarak benda = s jarak bayangan = y jarak fokus = f jari" = r perbesaran = m Diket : s = 15 cm m = 2 kali Ditanya : r Jwb : m = y/s 2 = y/15 30 = y 2f = r 1/f = 1/s + 1/y 1/f = 1/15 + 1/30 1/f = 2/30 + 1/30 1/f = 3/30 f = 30/3 f = 10 2f = r 2 × 10 = r 20 = r
jarak benda = s
jarak bayangan = y
jarak fokus = f
jari" = r
perbesaran = m
Diket :
s = 15 cm
m = 2 kali
Ditanya : r
Jwb :
m = y/s
2 = y/15
30 = y
2f = r
1/f = 1/s + 1/y
1/f = 1/15 + 1/30
1/f = 2/30 + 1/30
1/f = 3/30
f = 30/3
f = 10
2f = r
2 × 10 = r
20 = r
so = 15 cm
M = 2
Dit : R
Jawab :
si = M . so
si = 2 . 15
si = 30 cm
1/f = 1/so + 1/si
1/f = 1/15 + 1/30
1/f = 2/30 + 1/30
1/f = 3/30
f = 30/3 = 10 cm
R = 2f = 2 . 10
R = 20 cm