Question

Quizz
Jika:
y = 3³
x = 1
u = 5²
k= 2²

Maka, ³√y + x × u + (k×k) + k =..

Note: Selesai 1 hari, besok lanjut lagi..​

Answer 1

Jawaban:

Penyelesaian :

Dik :

• Y : 3³ = 3 × 3 × 3 = 9 × 3 = 27

• X : 1

• U : 5² = 5 × 5 = 25

• K : 2² = 2 × 2 = 4

Dit :

• ³√y + x × u + ( k × k ) + k = ?

Jawab :

• ³√y + x × u + ( k × k ) + k

• = ³√3³ + 1 × 5² + ( 2² × 2² ) + 2²

• = ³√27 + 1 × 25 + ( 4 × 4 ) + 4

• = 27 + 1 × 25 + 16 + 4

• = 27 + ( 1 × 25 ) + 16 + 4

• = 27 + 25 + 16 + 4

• = ( 27 + 25 ) + 16 + 4

• = 52 + 16 + 4

• = 52 + ( 16 + 4 )

• = 52 + 20

• = 72

Answer 2

Jawaban:

Penyelesaian Soal UvU :

Diketahui :

Jika:

y = 3³

x = 1

u = 5²

k= 2²

Ditanya :

Maka, ³√y + x × u + ( k × k) + k =..

Dijawab :

³√y + x × u + ( k × k ) + k

= ³√3³ + 1 × 5² + ( 2² × 2² ) + 2²

= ³√3³ + 1 × 5² + (( 2 × 2 ) × ( 2 × 2 )) + 2²

= ³√3³ + 1 × 5² + ( 4 × 4 ) + 2²

= ³√3³ + 1 × ( 5 × 5 ) + 16 + ( 2 × 2 )

= ³√( 3 × 3 × 3 ) + 1 × 25 + 16 + 4

= ³√( 9 × 3 ) + 1 × 25 + 16 + 4

= ³√27 + 1 × 25 + 16 + 4

= 27 + 1 × 25 + 16 + 4

= 27 + ( 1 × 25 ) + 16 + 4

= 27 + 25 + 16 + 4

= 52 + 16 + 4

= 68 + 4

= 72