Jawab:Suku ke-12 baris = 404
Penjelasan dengan langkah-langkah:Diketahui baris aritmatika bertingkat{8, 14, 26, 44, ....}
a = 8 14 26 44b = 6 12 18c = 6 6
a = 8, b = c = 6
Tentukan suku ke-12 (U₁₂){n = 12}dengan rumusUn = a + b(n-1) + (c(n-1)(n-2)/2)Karena b = c, makaUn = a + b(n-1) + (b(n-1)(n-2)/2)Un = a + (b(n-1) (1 + ((n-2)/2)))U₁₂ = 8 + (6(12-1) (1 + ((12-2)/2)))U₁₂ = 8 + (6(11) (1 + (10/2)))U₁₂ = 8 + (66 (1 + 5))U₁₂ = 8 + (66 (6))U₁₂ = 8 + 396U₁₂ = 404
Suku ke-12 baris = 404(xcvi)
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Verified answer
Jawab:
Suku ke-12 baris = 404
Penjelasan dengan langkah-langkah:
Diketahui baris aritmatika bertingkat
{8, 14, 26, 44, ....}
a = 8 14 26 44
b = 6 12 18
c = 6 6
a = 8, b = c = 6
Tentukan suku ke-12 (U₁₂)
{n = 12}
dengan rumus
Un = a + b(n-1) + (c(n-1)(n-2)/2)
Karena b = c, maka
Un = a + b(n-1) + (b(n-1)(n-2)/2)
Un = a + (b(n-1) (1 + ((n-2)/2)))
U₁₂ = 8 + (6(12-1) (1 + ((12-2)/2)))
U₁₂ = 8 + (6(11) (1 + (10/2)))
U₁₂ = 8 + (66 (1 + 5))
U₁₂ = 8 + (66 (6))
U₁₂ = 8 + 396
U₁₂ = 404
Suku ke-12 baris = 404
(xcvi)