Penjelasan dengan langkah-langkah:
●Jika n berupa ganjil
1+2-3+4-5+6-...-n
= 1 + (-1) + (-1) + ...
= 1 + m(-1)
Dimana
n = 2m + 1
maka 1+2-3+4-5+....-n
= 1 + m(-1) = 1 + -½(n-1)
= ½(1-n) + 1
●Jika n berupa genap
= 1+2-3+4-5+6-...+n
= 1+2-3+4-5+6-...-(n-1)+n
= [½(1-(n-1) + 1] + n
= ½(2-n) + n + 1
= n - ½n + 2
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Penjelasan dengan langkah-langkah:
●Jika n berupa ganjil
1+2-3+4-5+6-...-n
= 1 + (-1) + (-1) + ...
= 1 + m(-1)
Dimana
n = 2m + 1
maka 1+2-3+4-5+....-n
= 1 + m(-1) = 1 + -½(n-1)
= ½(1-n) + 1
●Jika n berupa genap
= 1+2-3+4-5+6-...+n
= 1+2-3+4-5+6-...-(n-1)+n
= [½(1-(n-1) + 1] + n
= ½(2-n) + n + 1
= n - ½n + 2