Jawab:
84
Penjelasan dengan langkah-langkah:
Eksponen
7^x. 49^(7 - x) = 50^x
7^(x + 14) = (50 × 49)^x
(x + 14)log 7 = x (log 50 + log 49)
(x + 14)/x = ⁷log 50 + 2
14/x = ⁷log 50 + 1
x = 14/(1 + ⁷log 50)
x = 14 . log 7 / (log 7 + log 5 + log 10)
x = 7 . log 7² / (1 + log 35)
x = 7 log a / (1 + log b)
a + b = 7² + 35 = 84 ✔
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Jawab:
84
Penjelasan dengan langkah-langkah:
Eksponen
7^x. 49^(7 - x) = 50^x
7^(x + 14) = (50 × 49)^x
(x + 14)log 7 = x (log 50 + log 49)
(x + 14)/x = ⁷log 50 + 2
14/x = ⁷log 50 + 1
x = 14/(1 + ⁷log 50)
x = 14 . log 7 / (log 7 + log 5 + log 10)
x = 7 . log 7² / (1 + log 35)
x = 7 log a / (1 + log b)
a + b = 7² + 35 = 84 ✔