Jawab:
2√30
Penjelasan dengan langkah-langkah:
Trigonometri
(A)
(5 sin x + 12 cos y)² + (5 cos x + 12 sin y)²
= 25 (sin² x + cos²)x + 120 (sin x cos y + cos x sin y) + 144 (cos² y + sin² y)
= 169 + 120 sin (x + y)
(B)
= 13² + (5 cos x + 12 sin y)²
Lihat kesamaan letak pd (A) dan (B)
120 sin (x + y) = (5 cos x + 12 sin y)²
Maksimum → sin (x + y) = 1
Maka :
(5 cos x + 12 sin y)² = 120
5 cos x + 12 sin y = √120
5 cos x + 12 sin y = 2√30 ✔
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Jawab:
2√30
Penjelasan dengan langkah-langkah:
Trigonometri
(A)
(5 sin x + 12 cos y)² + (5 cos x + 12 sin y)²
= 25 (sin² x + cos²)x + 120 (sin x cos y + cos x sin y) + 144 (cos² y + sin² y)
= 169 + 120 sin (x + y)
(B)
(5 sin x + 12 cos y)² + (5 cos x + 12 sin y)²
= 13² + (5 cos x + 12 sin y)²
Lihat kesamaan letak pd (A) dan (B)
120 sin (x + y) = (5 cos x + 12 sin y)²
Maksimum → sin (x + y) = 1
Maka :
(5 cos x + 12 sin y)² = 120
5 cos x + 12 sin y = √120
5 cos x + 12 sin y = 2√30 ✔