1.) Langkah 1 : Mencari volume silinder.
[tex]v = \pi \times r {}^{2} \times t[/tex]
[tex] = \frac{22}{7} \times (70cm {}^{2}) \times 200cm [/tex]
[tex] = \frac{22}{7} \times 4.900cm {}^{2} \times 200cm[/tex]
[tex] = 3.080.000cm³[/tex]
Langkah 2 : Mencari volume kerucut.
[tex]v = \frac{1}{3} \times \pi \times r {}^{2} \times t[/tex]
[tex] = \frac{1}{3} \times \frac{22}{7} \times (70cm {}^{2} ) \times 75cm[/tex]
[tex] = 385.000cm {}^{3} [/tex]
Langkah 3 : Mencari volume tugu.
[tex]v \: tugu = v \:silinder \: + \: v \: kerucut[/tex]
[tex]3.080.000cm {}^{3} + 385.000cm {}^{3} [/tex]
[tex] = 3.465.000cm {}^{3} [/tex]
2.) [tex]l = \pi \: r {}^{2} [/tex]
[tex]r = 14m[/tex]
[tex] = \pi(14) {}^{2} [/tex]
[tex] = 616\pi[/tex]
[tex]k = \pi \: d(keliling \: lingkaran)[/tex]
[tex] = \pi(28)[/tex]
[tex]28\pi \div 4 = 7\pi(keliling \: \div jarak \: antar \: pohon)[/tex]
[tex] = 15.000 \div 7\pi(biaya \: dibutuhin)[/tex]
[tex] = 105.000\pi(660.000)[/tex]
[tex] \colorbox{black}{ \blue{ \boxed{ \tt{ \color{aqua}{answer \: by \: star97}}}}}[/tex]
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1.) Langkah 1 : Mencari volume silinder.
[tex]v = \pi \times r {}^{2} \times t[/tex]
[tex] = \frac{22}{7} \times (70cm {}^{2}) \times 200cm [/tex]
[tex] = \frac{22}{7} \times 4.900cm {}^{2} \times 200cm[/tex]
[tex] = 3.080.000cm³[/tex]
Langkah 2 : Mencari volume kerucut.
[tex]v = \frac{1}{3} \times \pi \times r {}^{2} \times t[/tex]
[tex] = \frac{1}{3} \times \frac{22}{7} \times (70cm {}^{2} ) \times 75cm[/tex]
[tex] = 385.000cm {}^{3} [/tex]
Langkah 3 : Mencari volume tugu.
[tex]v \: tugu = v \:silinder \: + \: v \: kerucut[/tex]
[tex]3.080.000cm {}^{3} + 385.000cm {}^{3} [/tex]
[tex] = 3.465.000cm {}^{3} [/tex]
2.) [tex]l = \pi \: r {}^{2} [/tex]
[tex]r = 14m[/tex]
[tex] = \pi(14) {}^{2} [/tex]
[tex] = 616\pi[/tex]
[tex]k = \pi \: d(keliling \: lingkaran)[/tex]
[tex] = \pi(28)[/tex]
[tex]28\pi \div 4 = 7\pi(keliling \: \div jarak \: antar \: pohon)[/tex]
[tex] = 15.000 \div 7\pi(biaya \: dibutuhin)[/tex]
[tex] = 105.000\pi(660.000)[/tex]
[tex] \colorbox{black}{ \blue{ \boxed{ \tt{ \color{aqua}{answer \: by \: star97}}}}}[/tex]