BC = 25
AC = 20
AB = ?
AB = √BC² - AB²
AB = √25² - 20²
AB = √625 - 400
AB = √225
AB = 15 cm
Jawab:15 cm
Penjelasan dengan langkah-langkah:Diketahui:ΔABC siku-siku di AJika BC (c) = 25 cmdan AB (b) = 20 cmTentukan AC (a)
Pythagoras : a² = c² - b²a² = 25² - 20²a² = 625-400a² = 225a = √225a = 15 cm
Request nih:∫x³cos(x²) dx = .............[[ KLF ]]
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BC = 25
AC = 20
AB = ?
AB = √BC² - AB²
AB = √25² - 20²
AB = √625 - 400
AB = √225
AB = 15 cm
Jawab:
15 cm
Penjelasan dengan langkah-langkah:
Diketahui:
ΔABC siku-siku di A
Jika BC (c) = 25 cm
dan AB (b) = 20 cm
Tentukan AC (a)
Pythagoras :
a² = c² - b²
a² = 25² - 20²
a² = 625-400
a² = 225
a = √225
a = 15 cm
Request nih:
∫x³cos(x²) dx = .............
[[ KLF ]]