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Materi: VektorJawaban C (jika salah, hapus aja jawaban saya. Agak ragu hehe)
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Mapel : MatematikaKelas : XII SMA
Bab : Vektor
Pembahasan :
Perhatikan gambar diketahui :
G titik berat segitiga dan D adalah titik tengah BC
Maka...
BD : DC = 1 : 1
Vektor AD = [1(AB) + 1(AC)]/(1 + 1)
Vektor AD = [1(a) + 1(b)]/2
Vektor AD = (a + b)/2
Ditanya AG ?
AG = 2/3[(a + b)/2] = 1/3(a + b)
Jawaban : C