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1/Rp₁ = 1/12 + 1/6
1/Rp₁ = 1/12 + 2/12
1/Rp₁ = 3/12
Rp₁ = 12/3
Rp₁ = 4 Ω
* Serikan Rp₁ dengan resistor 5 Ω
Rs₁ = Rp₁ + 5
Rs₁ = 4 + 5
Rs₁ = 9 Ω
* Serikan resistor 15 Ω dengan 3 Ω
Rs₂ = 15 + 3
Rs₂ = 18 Ω
* Paralelkan Rs₁ dengan Rs₂
1/Rp₂ = 1/Rs₁ + 1/Rs₂
1/Rp₂ = 1/9 + 1/18
1/Rp₂ = 2/18 + 1/18
1/Rs₂ = 3/18
Rs₂ = 18/3
Rs₂ = 6 Ω
* Serikan Rs₂ dengan resistor 4 Ω
R tot = Rs₂ + 4
R tot = 6 + 4
R tot = 10 Ω
Jadi, besar hambatan totalnya adalah 10 Ω (Jawaban B)
1/Rp1 = 1/12 + 1/6
= 1 + 2
12
Rp1 = 12 / 3
= 4
Rp1 dan FG = Seri (Rs1), sehingga
Rs1 = 4 + 5 = 9
AB dan BC = Seri (Rs2), sehingga
Rs2 = 15 + 3 = 18
Rs1 dan Rs2 = Pararel (Rp2), sehingga
1/Rp2 = 1/Rs1 + 1/Rs2
= 1/9 + 1/18
= 2 + 1
18
Rp2 = 18/3 = 6
Rp2 dan CD = Seri (RT), sehingga
RT = 6 + 4 = 10 ohm
Jawabannya yang B