danielajuarez99
Volumen: V = 30 cm x 10 x 15 cm= 4500cm³ Densidad del acero: d = 7.8 kg/cm³ (promedio) Masa del bloque: m = V d = 4500 x 7.8 = 35 1000 g = 35.1 kg Peso del bloque: F = m g = 35.1 x 7.8 = 273.78 N
Areas de las caras: A1 = 30 x 15= 450cm² = 450 x 10^-4 m² A2 = 15 x 10 = 150 cm² = 150 x 10^-4 m² A3 = 10 x 30 = 300 cm² = 300 x 10^-4 m²
Aplicando la formula p = F/A se obtiene: p1 = F/A1 = 273.78 / 450 x10^-4 = 6.084x 10^-5 N/m² p2 = F/A2 =273.78 / 150 x10^-4 = 1.8252 x 10^-4N/m² p3 = F/A3 = 273.78 / 300 x10^-4 = 9.126 x 10^-5 N/m²
Densidad del acero: d = 7.8 kg/cm³ (promedio)
Masa del bloque: m = V d = 4500 x 7.8 = 35 1000 g = 35.1 kg
Peso del bloque: F = m g = 35.1 x 7.8 = 273.78 N
Areas de las caras:
A1 = 30 x 15= 450cm² = 450 x 10^-4 m²
A2 = 15 x 10 = 150 cm² = 150 x 10^-4 m²
A3 = 10 x 30 = 300 cm² = 300 x 10^-4 m²
Aplicando la formula p = F/A se obtiene:
p1 = F/A1 = 273.78 / 450 x10^-4 = 6.084x 10^-5 N/m²
p2 = F/A2 =273.78 / 150 x10^-4 = 1.8252 x 10^-4N/m²
p3 = F/A3 = 273.78 / 300 x10^-4 = 9.126 x 10^-5 N/m²