Jawab:b = 6, b = -³/₂
Penjelasan:a×a+b×a=27,--> a(a+b) = 27 (pers i)JIKA NILAI a=b-3--> a = b-3 (pers ii)Maka nilai b adalah?
a(a+b) = 27Substitusi pers i dgn pers ii(b-3)(b-3+b) = 27(b-3)(2b-3) = 272b²-3b-6b+9 = 272b²-3b-6b+9-27 = 02b²-9b-18 = 0b²-9b-18(2) = 0b²-9b-36 = 0(2b-12)(2b+3) = 02b = 12, 2b = -3b = ¹²/₂, b = -³/₂b = 6, b = -³/₂
(Xcvi)
Penjelasan dengan langkah-langkah:
DUO VARIABEL
a×a + b×a = 27, a = b – 3
a² + ab = 27
(b – 3)² + b(b – 3) = 27
b² – 6b + 9 + b² – 3b = 27
2b² – 9b = 27 – 9
2b² – 9b – 18 = 0
(2b + 3)(b – 6) = 0
b = –3/2 atau b = 6
b = –3/2
a = –3/2 – 3
a = –4½
(–9/2)² + (–9/2)×(–3/2) = 27
81/4 + 27/4 = 27
108/4 = 27 ✔
b = 6
a = 6 – 3
a = 3
3² + 3×6 = 27
9 + 18 = 27 ✔
jadi,
nilai b = –3/2 atau b = 6
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Jawab:
b = 6, b = -³/₂
Penjelasan:
a×a+b×a=27,
--> a(a+b) = 27 (pers i)
JIKA NILAI a=b-3
--> a = b-3 (pers ii)
Maka nilai b adalah?
a(a+b) = 27
Substitusi pers i dgn pers ii
(b-3)(b-3+b) = 27
(b-3)(2b-3) = 27
2b²-3b-6b+9 = 27
2b²-3b-6b+9-27 = 0
2b²-9b-18 = 0
b²-9b-18(2) = 0
b²-9b-36 = 0
(2b-12)(2b+3) = 0
2b = 12, 2b = -3
b = ¹²/₂, b = -³/₂
b = 6, b = -³/₂
(Xcvi)
Penjelasan dengan langkah-langkah:
DUO VARIABEL
a×a + b×a = 27, a = b – 3
a² + ab = 27
(b – 3)² + b(b – 3) = 27
b² – 6b + 9 + b² – 3b = 27
2b² – 9b = 27 – 9
2b² – 9b – 18 = 0
(2b + 3)(b – 6) = 0
b = –3/2 atau b = 6
b = –3/2
a = –3/2 – 3
a = –4½
a² + ab = 27
(–9/2)² + (–9/2)×(–3/2) = 27
81/4 + 27/4 = 27
108/4 = 27 ✔
b = 6
a = 6 – 3
a = 3
a² + ab = 27
3² + 3×6 = 27
9 + 18 = 27 ✔
jadi,
nilai b = –3/2 atau b = 6