1. The sum of two numbers is 30. Their product is 81. What are the two numbers? 2. The quotient of two numbers is 3. Their product is 75. What are the two numbers?
Penjelasan dengan langkah-langkah: Yo ndak tahu kok tanya saya? (Xcvi)
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Just kidding Jawab: (1.) --> There are 2 pairs of two numbers: {3, 27} and {27, 3} (2.) --> There are 2 pairs of two numbers: {-15, -5} and {15, 5}
Penjelasan dengan langkah-langkah: (1.) a+b = 30, ab = 81 -> b = 81/a a + (81/a) = 30 -> (a²/a) + (81a/a) = (30a/a) a² + 81 = 30a -> a² - 30a + 81 = 0 Aa² + Ba + C = 0 ∴ A = 1, B = -30, C = 81 p and q are roots, pq = C/A, p+q = -B/A pq = 81/1, p+q = -(-30)/1 ; therefore , pq = 81, p+q = 30 ∴ p = 27, q = 3 a+b = 30, ab = 81 (same) p = 3, q = 27 --> There are 2 pairs of two numbers: {3, 27} and {27, 3}
(2.) a/b = 3 -> a = 3b ab = 75, b(3b) = 75, 3b² = 75 b = √(75/3), b = √25, b = ±5 b = {-5, 5} a = 3b, a = {3(-5), 3(5)} a = {-15, 15} --> There are 2 pairs of two numbers: {-15, -5} and {15, 5}
Jawab:
Yo ndak tahu kok tanya saya?
Penjelasan dengan langkah-langkah:
Yo ndak tahu kok tanya saya?
(Xcvi)
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Just kidding
Jawab:
(1.) --> There are 2 pairs of two numbers:
{3, 27} and {27, 3}
(2.) --> There are 2 pairs of two numbers:
{-15, -5} and {15, 5}
Penjelasan dengan langkah-langkah:
(1.) a+b = 30, ab = 81 -> b = 81/a
a + (81/a) = 30 -> (a²/a) + (81a/a) = (30a/a)
a² + 81 = 30a -> a² - 30a + 81 = 0
Aa² + Ba + C = 0 ∴ A = 1, B = -30, C = 81
p and q are roots, pq = C/A, p+q = -B/A
pq = 81/1, p+q = -(-30)/1 ; therefore ,
pq = 81, p+q = 30 ∴ p = 27, q = 3
a+b = 30, ab = 81 (same) p = 3, q = 27
--> There are 2 pairs of two numbers:
{3, 27} and {27, 3}
(2.) a/b = 3 -> a = 3b
ab = 75, b(3b) = 75, 3b² = 75
b = √(75/3), b = √25, b = ±5
b = {-5, 5}
a = 3b, a = {3(-5), 3(5)}
a = {-15, 15}
--> There are 2 pairs of two numbers:
{-15, -5} and {15, 5}
(xcvi)