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P = P₀ + ρgh
Datos
P₀ = 1 atm = 101325 Pa
ρ = 1000 kg/m³
g = 9,8 m/s²
h = 35 m
Reemplazas y operas
P = P₀ + ρgh
P = 101325 Pa + (1000 kg/m³)(9,8 m/s²)(35 m)
P = 444325 Pa
Respuesta
La presion que soporta el submarinista sumergido es de 444325 Pa o de aproximadamente 4,38 atm