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x1 +1, x2 +1, x3+1, x4+1, y continúa x5+1
4, (x1+1)= 5, (x2+1)= 11, (x3+1)= 34, (x4+1)= 137, (137x5+1)= 686
Respuesta:
El número que continúa es 686