Luas Permukaan Tabung
2πr ( r + t )
2 × 3,14 × 10 ( 10 + 30 )
6,28 × 10 ( 40 )
62,8 ( 40 )
2.512 cm²
5! × 3!
( 5 × 4 × 3 × 2 × 1 ) × ( 3 × 2 × 1 )
( 20 × 6 ) × 6
120 × 6
720
Diketahui :
Ditanya :
Dijawab :
» Luas Permukaan Tabung «
→ Lp = 2 × π × r × ( r + t )
→ Lp = 2 × 3,14 × 10 cm×(10 cm+30 cm)
→ Lp = 62,8 cm × 40 cm
→ Lp = 2.512 cm²
Kesimpulan :
==================================
Penyelesaian :
→ 5! × 3!
→ = ( 5 × 4 × 3 × 2 × 1 ) × ( 3 × 2 × 1 )
→ = ( 20 × 3 × 2 × 1 ) × ( 6 × 1 )
→ = ( 60 × 2 × 1 ) × 6
→ = ( 120 × 1 ) × 6
→ = 720
I Hope This Help-!
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Luas Permukaan Tabung
2πr ( r + t )
2 × 3,14 × 10 ( 10 + 30 )
6,28 × 10 ( 40 )
62,8 ( 40 )
2.512 cm²
5! × 3!
( 5 × 4 × 3 × 2 × 1 ) × ( 3 × 2 × 1 )
( 20 × 6 ) × 6
120 × 6
720
JAWABAN
No.1
Diketahui :
Ditanya :
Dijawab :
» Luas Permukaan Tabung «
→ Lp = 2 × π × r × ( r + t )
→ Lp = 2 × 3,14 × 10 cm×(10 cm+30 cm)
→ Lp = 62,8 cm × 40 cm
→ Lp = 2.512 cm²
Kesimpulan :
==================================
No.2
Penyelesaian :
→ 5! × 3!
→ = ( 5 × 4 × 3 × 2 × 1 ) × ( 3 × 2 × 1 )
→ = ( 20 × 3 × 2 × 1 ) × ( 6 × 1 )
→ = ( 60 × 2 × 1 ) × 6
→ = ( 120 × 1 ) × 6
→ = 720
Kesimpulan :
I Hope This Help-!